# The train starts moving from a standstill with constant acceleration. On the first kilometer, its speed increased by 10 m / s.

September 20, 2021 | education

| **The train starts moving from a standstill with constant acceleration. On the first kilometer, its speed increased by 10 m / s. How much did it increase on the second kilometer?**

Given: uniformly accelerated movement from a state of rest; S1 (first distance) = 1000 m; V1 (first reached speed) = 10 m / s; S2 (second distance) = 2000 m.

Since the acceleration of a given train is constant, we express the speed at the end of the second kilometer of the track from the equality: V1 ^ 2 / 2S1 = a = V2 ^ 2/2 S2 and V2 = √ (V1 ^ 2 * S2 / S1) = √ (10 ^ 2 * 2000/1000) = 14.14 m / s.

The growth of speed on the second kilometer: ΔV2 = V2 – V1 = 14.14 – 10 = 4.14 m / s.

Answer: On the second kilometer, the speed will increase by another 4.14 m / s.

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